MCA NIMCET Number System Previous Year Question Paper and Solution with PDF

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MCA NIMCET Previous Year Questions (PYQs)

MCA NIMCET Number System PYQ

Qus : 1MCA NIMCET PYQ

The number (2217)₈ is equivalent to

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MCA NIMCET Previous Year PYQMCA NIMCET NIMCET 2021 PYQ

Solution

(2217)8 =(010010001111)8

Pair of 4 Bits

1111= F

1000=8

0100=4

(010010001111)8 =(48F)16

Qus : 2MCA NIMCET PYQ

The binary multiplication 00*11 will give

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MCA NIMCET Previous Year PYQMCA NIMCET NIMCET 2021 PYQ

Solution

0*3=0

Qus : 3MCA NIMCET PYQ

The binary equivalent of (234.125)₁₀?

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MCA NIMCET Previous Year PYQMCA NIMCET NIMCET 2020 PYQ

Solution

Qus : 4MCA NIMCET PYQ

Determine the octal equivalent of (432267)₁₀?

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MCA NIMCET Previous Year PYQMCA NIMCET NIMCET 2020 PYQ

Solution

Qus : 5MCA NIMCET PYQ

One Exabyte is equal to …

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MCA NIMCET Previous Year PYQMCA NIMCET NIMCET 2020 PYQ

Solution

Qus : 6MCA NIMCET PYQ

The logic XOR operation of (4AC0)₁₆ and (B53F)₁₆ results

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MCA NIMCET Previous Year PYQMCA NIMCET NIMCET 2020 PYQ

Solution

Qus : 7MCA NIMCET PYQ

Equivalent of the decimal number (25.375)10 in binary form

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MCA NIMCET Previous Year PYQMCA NIMCET NIMCET 2023 PYQ

Solution

Decimal to Binary Conversion

? Given: Convert (25.375)₁₀ to binary.

? Step-by-step:

Integer Part (25):
Divide by 2 repeatedly:

25 ÷ 2 = 12 remainder 1  
12 ÷ 2 = 6  remainder 0  
6  ÷ 2 = 3  remainder 0  
3  ÷ 2 = 1  remainder 1  
1  ÷ 2 = 0  remainder 1

→ Binary: 11001

Fractional Part (0.375):
Multiply by 2 repeatedly:

0.375 × 2 = 0.75   → 0  
0.75 × 2  = 1.5    → 1  
0.5 × 2   = 1.0    → 1

→ Binary: .011

✅ Final Binary Answer: (25.375)₁₀ = (11001.011)₂

Qus : 8MCA NIMCET PYQ

A family has several children. Each boy in this family has as many sisters as brothers, but each girl has twice as many brothers as sisters. How many brothers and sisters are there?

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MCA NIMCET Previous Year PYQMCA NIMCET NIMCET 2016 PYQ

Solution

Qus : 9MCA NIMCET PYQ

A Group of 630 children are seated in n rows for a group photo session. Each row contains three less children than the row in front of it. Which one of the following number of rows is not possible?

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MCA NIMCET Previous Year PYQMCA NIMCET NIMCET 2016 PYQ

Solution

Qus : 10MCA NIMCET PYQ

405 sweets were distributed equally among a group of children such that the number of sweets received by each child is one-fifth of the number of children. The number of children in the group is

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MCA NIMCET Previous Year PYQMCA NIMCET NIMCET 2016 PYQ

Solution

Qus : 11MCA NIMCET PYQ

What is the missing number in the series 4, 7, 11, 18, 29, 47, __________, 123, 199?

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MCA NIMCET Previous Year PYQMCA NIMCET NIMCET 2016 PYQ

Solution

Qus : 12MCA NIMCET PYQ

A bus starts from its depot filled to seating capacity. It stops at a point A where 1/6th of the passengers alight and 10 board the bus. At point B, 1/5th of the passengers alight and 3 board the bus. At point C which is the last stop, all the 55 passengers alight. The capacity of the bus is

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MCA NIMCET Previous Year PYQMCA NIMCET NIMCET 2016 PYQ

Solution

Qus : 13MCA NIMCET PYQ

If all the 6's are replaced by 9's, then the algebraic sum of all the numbers from 1 to 100 (both inclusive)

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MCA NIMCET Previous Year PYQMCA NIMCET NIMCET 2016 PYQ

Solution

Qus : 14MCA NIMCET PYQ

The greatest number which on dividing 1657 and 2037 leaves remainders 6 and 5 respectively is

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MCA NIMCET Previous Year PYQMCA NIMCET NIMCET 2022 PYQ

Solution

The first number = (1657 - 6) = 1651

Second number = (2037 - 5) = 2032

Taking the HCF of two numbers 1651, 2032 we get 127.

So, if we divide 1657 and 2037 by 127 we will get remainders 6 and 5 respectively.

Qus : 15MCA NIMCET PYQ

Suppose the largest n bit number requires ‘d’ digits in decimal representation. Which of the following relations between ‘n’ and ‘d’ is approximately correct

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MCA NIMCET Previous Year PYQMCA NIMCET NIMCET 2022 PYQ